Module:Sandbox/Arcangelus

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Description

This is a doc attached to my sandbox. I'll use it to see the effects of my changes W/o messing something important

NOTE: LUA is usually slower than ParserFunctions for short statements. The factor varies from 7-1 to 2-1.
Lua only is an advantage to long statements, nested logic, loops (maybe others case i don't see right now).

expr only uses 1 Preprocessor visited node count, in general. Variables may change that.

---

function p._TableRow(skillBase, skillBonus, statMin, statMax, capImportance, capLimit, resultCols, LV, Ln)

---

--[[
This module implements the functions of Template:Thought
]]

local p = {}
local getArgs = require('Module:Arguments').getArgs

--[[ The template argument goes to "main" 
Only this funcion will work when invoked. This is case sensitive.
What it does is obtain the data from the wiki to a fomrat readable by other functions]]

function p.main(frame)
	local args = getArgs(frame)
	local desc = tostring(args["desc"])
	local label = tostring(args["label"])
	local duration = tonumber(args["duration"])
	local stack = tonumber(args["stack"])
	local multi = tonumber(args["multi"]) or 1
--[[ The advantage of adding values to an empty list rather than defining a list
	with the correct values is that no nil values will get into the list this way.
	This means that values don't have to be consecutive.
	EX: value9 is valid w/o defining value2 to value8.
	]]
	local valores = {}
	valores[#valores+1]=args["value"]
	valores[#valores+1]=args["value2"]
	valores[#valores+1]=args["value3"]
	valores[#valores+1]=args["value4"]
	valores[#valores+1]=args["value5"]
	valores[#valores+1]=args["value6"]
	valores[#valores+1]=args["value7"]
	valores[#valores+1]=args["value8"]
	valores[#valores+1]=args["value9"]
	if tonumber(args["value"]) then
		return p._main(desc, label, duration, stack, multi, valores)
		else
			return "<big><b>Missing value. Please, define a numerical value to use.</b></big>"
	end
end

--[[
_main function decides the kind of thought this will be and returns the final output
If the are several defines values, then it uses the Thought function
If only value is defined, then:
	- If both stack and the multiplier "multi" are 1, it gives a result early.
		multi defaults to 1 when not defined (or invalid)
	- Otherwise, it calls the stacks function.
]]

function p._main(desc, label, duration, stack, multi, valores)
	local final_string = duration and {duration, " [[mood]] for ", duration, " [[Time|days]]" } or {" [[mood]]"}
	local middle_string = {'<abbr title="', desc, '"><i>', (label:gsub("^%l", string.upper)), '</i></abbr>' }
	-- "valores" is a list of all values given to the function.
	-- This checks if a second value exist
	if valores[2] then
		return p.Thought(valores) --..middle_string..final_string
	else --Only initial value defined
		if stack==1 and multi==1 then
			local value = valores[1]
			if tonumber(value)>0 then
				return '<b><font color="forestgreen">'..value..'</font></b> '..middle_string..final_string
			elseif tonumber(value) == 0 then
				return '<b>'..value..'</b> '..middle_string..final_string
			else
				return '<b><font color="firebrick">'..value..'</font></b> '..middle_string..final_string
			end
		end
		return p.stacks(stack, multi, valores[1])..middle_string..final_string
	end
end

--[[
The "Thought" function returns a string if more than 1 value was defined.
It iterates through all the values defined (contained on the list "valores") 
For each element:
1.- If it is a valid number, then it valuates what kind of number it is.
1.2.- If it is, it then decides what color it need. Currently, it returns:
	Green for positive, Red for negative, None for 0.
2.- It it is not a valid number, it returns the value bolded and large. The idea is to make the mistake obvious.
3.- Once all values are checked, it concatenates all results, with some extras to make sense.
This last part is what it returns.
]]

function p.Thought(valores)
	local valores_buscados={}
	for i, j in ipairs(valores) do
		local vx = valores[i]
		local vy = ""
		if tonumber(vx) then -- A number.
			vy = tonumber(vx)<0 and '<b><font color="firebrick">'..vx.."</font></b>" or tonumber(vx)>0 and '<b><font color="forestgreen">'..vx.."</font></b>" or '<b>0</b>'
		else
			vy='<big><b>'..vx.."</b></big>" --The idea is to prevent a hard to track error
		end
		valores_buscados[#valores_buscados+1]=vy
	end
	return "<b>"..table.concat(valores_buscados,"<b>/</b>").."</b> "..table.concat(middle_string,"")..table.concat(final_string,"")
end

--[[
The "stacks" function return a string for the case that only 1 value was defined.
1.  If a stack value was defined:
1.1 Is stack equal to 1
1.2 Any other case.
2.  If a stack was not defined, then check the multiplier
2.1 If the multiplier is equal or above one
2.2 If the multiplier is below 1.

Finally, some final code to decide what color to use.
1. Green (forestgreen) for positive.
2. None for 0.
3. Red (firebrick) for negatives.
The retuned value is rounded half-down. (Meaning 0.5 -> 0 )
	string.format("%.2f", number))
To combat that, I add 0.001 to the number calculated. It should be enough.
]]

function p.stacks(stack, multi, value)
	local text=""
	if stack then
		if multi == 1 then
			if stack ~= 1 then 
				text = "Stacking "..stack.." times for a maximum of "..tostring(value*stack)
			end
		else
			text = "Stacking "..stack.." times with a "..multi.." multiplier for maximum of "..string.format("%.2f", value*( 1 - multi^stack)/(1 - multi) + 0.001)
		end
	else
		if multi >= 1 then --I want to avoid the case of really large numbers.
			text = "Stacking infinitely"
		else
			text = "Stacking with a "..multi.." multiplier for maximum of "..string.format("%.2f", value*( 1 - multi^100)/(1 - multi) + 0.001)
		end
	end

	if tonumber(value)>0 then
		return '<abbr title="'..text..'"><b><font color="forestgreen">'..value..'</font></b></abbr> '
	elseif tonumber(value) == 0 then
		return '<abbr title="'..text..'"><b>'..value..'</b></abbr> '
	else
		return '<abbr title="'..text..'"><b><font color="firebrick">'..value..'</font></b></abbr> '
	end
end

--This last part outputs the actual result. W/O it, it gives an error.
return p