Module:Thought

From RimWorld Wiki
Revision as of 04:44, 16 August 2024 by Arcangelus (talk | contribs) (This is either clever or a dumpster fire. I want to know if this is a viable way of writing it.)
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)
Jump to navigation Jump to search

Documentation for this module may be created at Module:Thought/doc

local p = {}
valores_ingresados={"value", "value2", "value3", "value4", "value5", "value6", "value7", "value8", "value9" }
-- "stack, "duration", "multi", "label", "desc", "label"

function p.Main(frame)
	Part1=""
	if frame.args["value"] then
		if frame.args["value2"] then
			return p.Thought(frame)..'<abbr title="'..frame.args["desc"]..'">'..frame.args["label"]:gsub("^%l", string.upper)..'</abbr>'.." [[mood]]"
		else
			Part1='<abbr title="'..p.stacks(frame)..'"> '..'<abbr title="'..frame.args["desc"]..'">'..frame.args["label"]:gsub("^%l", string.upper)..'</abbr>'.." [[mood]]"
		end
	end
	
end

function p.Thought(frame)--This is just the value section.
	valores_buscados={}
	for i, j in ipairs(valores_ingresados) do
		local vz = valores_ingresados[i]
		local vx = frame.args[vx]
		local vy = ""
		if vx then -- Not a nil
			if tonumber(vx) then --A number
				if tonumber(vx)<0 then vy='<b><font color="firebrick">'..vx.."</font></b>" else vy='<b><font color="forestgreen">'..vx.."</font></b>" end
			else vy='<b>'..vx.."</b>" --The idea is to prevent a hard to track error
			end
			valores_buscados[#valores_buscados+1]=vx
		end
	end
	return "<b>"..table.concat(valores_buscados,"<b>/</b>").."</b>"
end

function p.stacks(frame)--This is just the stacking section.
	local stack = frame.args["stack"]
	local multi= frame.args["multi"]
	if frame.args["stack"] then
		local va= "Stacking "..stack.."times "
		if frame.args["multi"] == 1 then
			text= "for a maximum of "..tostring(frame.args["value"]*stack)
		else
			text= "with a "..multi.." multiplier for maximum of"..tostring(frame.args["value"]*( 1 - multi^stack)/(1 - multi))
		end
		return va..text
	else
		if frame.args["multi"] == 1 then --What about a mult above 1?
			text = "Stacking infinitely"
		else
			text = "Stacking with a "..multi.." multiplier for maximum of "..tostring( frame.args["value"]*( 1 - multi^100)/(1 - multi) )
		end
		return text
	end
end