Module:Thought

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Revision as of 05:57, 16 August 2024 by Arcangelus (talk | contribs)
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Documentation for this module may be created at Module:Thought/doc

local p = {}
local getArgs = require('Module:Arguments').getArgs
-- "stack, "duration", "multi", "label", "desc", "label"
valores_ingresados={"value", "value2", "value3", "value4", "value5", "value6", "value7", "value8", "value9" }


function p.Main(frame)
	local args = getArgs(frame)
	return tostring(args[value]) --.." T_T "
--	return p._main(args)
end

function p._main(desc, label, duration, stack, multi, value, value2, value3, value4, value5, value6)
	if args(value) then
		if args[value2] then
			return p.Thought(args)..'<abbr title="'..desc..'">'..label..gsub("^%l", string.upper)..'</abbr>'.." [[mood]]"
		else
			return '<abbr title="'..p.stacks(args)..'"> '..'<abbr title="'..desc..'">'..label..gsub("^%l", string.upper)..'</abbr>'.." [[mood]]"
		end
	else
		return args.." T_T "
	end
end

function p.Thought(args)--This is just the value section.
	local valores_buscados={}
	for i, j in ipairs(valores_ingresados) do
		local vx = valores_ingresados[i]
		local vy = ""
		if vx then -- Not a nil
			if tonumber(vx) then --A number
				if tonumber(vx)<0 then vy='<b><font color="firebrick">'..vx.."</font></b>" else vy='<b><font color="forestgreen">'..vx.."</font></b>" end
			else vy='<b>'..vx.."</b>" --The idea is to prevent a hard to track error
			end
			valores_buscados[#valores_buscados+1]=vx
		end
	end
	return "<b>"..table.concat(valores_buscados,"<b>/</b>").."</b>"
end

function p.stacks(args)--This is just the stacking section.
	if stack then
		local va= "Stacking "..stack.."times "
		if multi == 1 then
			text= "for a maximum of "..tostring(value*stack)
		else
			text= "with a "..multi.." multiplier for maximum of"..tostring(value*( 1 - multi^stack)/(1 - multi))
		end
		return va..text
	else
		if multi == 1 then --What about a mult above 1?
			text = "Stacking infinitely"
		else
			text = "Stacking with a "..multi.." multiplier for maximum of "..tostring(value*( 1 - multi^100)/(1 - multi) )
		end
		return text
	end
end

return p